Read the following problem: The length of one side of a rectangle is 29 feet. The width of one side of the rectangle is 33 feet. What is the perimeter and the area for the rectangle?
Set up a polynomial formula with the situational values for the perimeter. The formula for perimeter is P = 2L + 2W; the perimeter equals two times the length plus two times the width.
Plug in the values. The perimeter is unknown, so use P to represent it. The length is 29 and the width is 33. The polynomial formula for the perimeter is P = 2(29) + 2(33).
Apply the distributive property to solve for the parentheses: (2 x 29) + (2 x 33) = 58 + 66. Simplify the formula: P = 124. The perimeter is 124 feet.
Set up a polynomial formula for the area of the rectangle. The formula is A = LW, or area equals length times width. Plug in the values: A = 29 x 33.
Simplify the equation: A = 957. The area of the rectangle is 957 square feet.