How to Graph 3rd Degree Polynomials

In math, polynomial equations combine variables raised to positive integer exponents. The "degree" of a polynomial is defined by the highest variable exponent, known as the leading term. For example, the equation 2x^2 + x - 6 is a second-degree polynomial, because two is the highest exponent. The leading term in a third-degree polynomial has an exponent of three. The full declaration for third-degree polynomials is the form f(x) = ax^3 + bx^2 + cx + d, where a, b, c and d are real numbers. Graphs of third-degree polynomials can be determined by identifying the leading coefficient a, the constant d, and the x values where the equation is equal to zero.

Things You'll Need

  • Calculator
  • Paper
  • Pen or pencil
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Instructions

    • 1

      Identify the leading coefficient (a) and the constant term (d) in the equation. The Rational Zero principle states that any zeros of the equation will be a rational number using factors of the leading coefficient as the numerator and factors of the constant term as the denominator.

    • 2

      Factor the leading coefficient and constant term. For example, for the equation 2x^3 + 2x^2 + 3x -6, the leading coefficient is 2 with factors 1, -1, 2 and -2. The constant is -6, so the factors are 1, -1, 2, -2, 3, -3, 6 and -6. Thus, the total set of factors is 1, -1, 2, -2, 3, -3, 6 and -6.

    • 3

      Test each factor for a zero output in the function. Mark which values produce a zero. These values are the x-intercepts of the equation.

    • 4

      Factor the equation into its lowest forms using polynomial factoring methods. The factoring process attempts to reduce the equation into a form with no exponents. This will depend on the type of equation and the leading coefficients; e.g., x^3 + 2x^2 -- x -- 2 = (x -- 1)(x + 1)(x + 2).

    • 5

      Use the factored equation to determine the multiplicity or number of each x-intercept. An x-intercept can be identified by taking each factored grouping and setting it equal to zero. For example, the equation x(x -- 2)(x + 3) would have x-intercepts of 0, 2 and -3 with multiplicities of one. The equation (x -- 1)(x -- 1)(x + 1) would have a multiplicity two x-intercept 1 and a multiplicity one x-intercept -1.

    • 6

      Determine the transitivity of each x-intercept. If an x-intercept has odd multiplicity, it is considered transitive and is a point where the equation will cross the x-axis. Even multiplicity determines an intransitive x-intercept, where the equation will not cross the x-axis.

    • 7

      Locate the leading coefficient (a). Negative coefficients create a graph line under the x-axis beyond the largest zero. If the coefficient is positive, it will be above the x-axis.

    • 8

      On graph paper or on a set of axes, plot the x-intercepts.

    • 9

      Enter more values between the highest and lowest zeros into the equation to plot additional points. More points will create a smoother graph line.

    • 10

      Draw a line roughly fitting the plotted points.

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