Assume an example curve equation of f(x) = x^2 + 3x - 4, where the notation 2x^2 is x squared. In our example we want the tangent at the point x = 4.
Apply the calculus rule that the equation of tangent line to a given curve f(x) is y = f'(t)(x-t) + f(t) where t is the x coordinate of the tangent. To find f'(x), we need to compute the derivative of the curve's equation, which becomes f'(x) = 2x + 3
Compute the slope using the f'(x) = 2x + 3 from Step 2 by substituting our example tangent point of x = 4. f'(4) = (2 * 4) + 3 = 8 + 3 = 11.
Compute f(4) = (4*4) + (3*4) - 4 = 16 + 12 - 4 = 24
Apply the values we just computed in Steps 3 and 4 back into the formula: y = f'(t)(x-t) + f(t). y = 11(x - 4) + 24 = 11x - 20. Thus the equation of the tangent line that intersects the curve f(x) = x^2 + 3x - 4 at x = 4 is y = 11x - 20.