How to Calculate an Improper Integral

Improper integrals have positive or negative infinity in one or both of the bounds of the integrals. It is difficult to imagine calculating the area of a graph stretching to positive or negative infinity, but it is possible with the use of infinite limits. Temporarily substitute a variable t in for the improper integral, then calculate the integral by taking the limit as t goes to infinity in the antiderivative of the function. For certain types of functions, this will result in a real number solution.

Instructions

    • 1

      Replace the improper integrand (∞ or -∞) with a placeholder variable in the improper integral. For example, in the integral from 1 to ∞ of 1 / x^2 dx, replace the ∞ integrand with to get the integral from 1 to t of 1/ x^2 dx.

    • 2

      Solve the definite integral from 1 to t by calculating the antiderivative of the function and evaluating it at values f(t) and f(1). In the above example, the antiderivative of 1 / (x^2) is -1/x. The integral is therefore equal to -1/t - (-1/1).

    • 3

      Simplify the expression in Step 2 by distributing factors, combining like terms, and reducing fractions. The expression -1/t - (-1/1) simplifies to -1/t + 1, or 1 - 1/t.

    • 4

      Take the limit of the simplified expression from Step 3 as the variable t goes to positive or negative infinity (whichever the sign of infinity the integrand you replaced with t in Step 1 had) and simplify the answer. In the above example, the limit as t goes to infinity of 1 - 1/t) is 1 - 0, or 1. The improper integral from 1 to ∞ of the function 1 / x^2 is therefore equal to 1.

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