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How to Solve Adding Fractions With Variables Attached

Algebra is about optimization. The use of algebra can be thought of as a simple machine that when fed information, pops out an answer. Whether adding rational algebraic expressions or solving polynomials of several degrees, it all goes back to the fundamental theorem of algebra. It states if f(x) is a polynomial of degree n where n > 0, then f has at least one zero or factor in the complex number system. The methods for solving these expressions are the "inner" workings of the simple machine. Jean Le Rond d'Alembert (1717-83) and Carl Friedrich Gauss (1777-1855) proved this theorem.

Things You'll Need

  • Pencil
  • Paper
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Instructions

  1. Adding Algebraic Expressions with a Common Denominator

    • 1

      Add the numerators of all expressions. For example, if given, (3x)/(2x + 1) + (5x -3)/(2x + 1) + (2x + 8)/ (2x + 1), write 3x + 5x - 3 + 2x + 8. Perform the addition. This yields 3x + 5x + 2x - 3 + 8, or 10x + 5.

    • 2

      Write the new expression with the sum of the numerators over the common denominator. In the example: (10x + 5) / (2x + 1).

    • 3

      Simplify the result. Factoring and reducing to lowest terms gives:

      (10x + 5) / (2x + 1) = [5(2x + 1)] / (2x + 1) = 5.

    Adding Algebraic Expressions without a Common Denominator

    • 4

      Find the least common denominator (LCD) of the terms by taking the least common multiple (LCM) of the individual denominators and multiplying them. For example, if given: [3 / (x + 2)] - [(2x) / (x - 3)], the LCD is (x + 2)(x - 3).

    • 5

      Rewrite each expression with the LCD. To achieve this and not change the values of any of the expressions, each expression must be multiplied by the LCD in the numerator and denominator.

      In the example:

      3 / (x + 2) becomes 3 (x - 3) / [(x + 2) (x - 3)] and 2x / (x - 3) becomes [2x (x + 2)] / [(x + 2) (x - 3)].

    • 6

      Add the numerators, performing all necessary multiplication and addition, combining like terms and writing the numerator in standard form. Keep the denominator the same.

      In the example:

      [3 (x - 3)] / [(x + 2) (x - 3)] + [2x (x + 2)] / [(x + 2) (x - 3)] =

      [3x - 9 + 2x^2 + 4x] /[ (x - 3) ( x + 2)] =

      [2x^2 + 7x - 9] /[ (x - 3) ( x + 2)].

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