Let's say the trait is eye color, with brown (B) being dominant and blue (b) being recessive.
* If one parent is heterozygous (Bb) and the other is homozygous dominant (BB): All offspring will have at least one B allele, meaning they will have brown eyes. There's a 100% chance of having brown eyes and a 0% chance of having blue eyes. However, 50% will be heterozygous (Bb) and 50% homozygous dominant (BB).
* If one parent is heterozygous (Bb) and the other is homozygous recessive (bb): There's a 50% chance the offspring will inherit the dominant B allele from the heterozygous parent and have brown eyes (Bb). There's a 50% chance the offspring will inherit the recessive b allele from both parents and have blue eyes (bb).
* If both parents are heterozygous (Bb): This is a classic Mendelian cross. The Punnett square shows the following probabilities:
* 25% chance of homozygous dominant (BB) - brown eyes
* 50% chance of heterozygous (Bb) - brown eyes
* 25% chance of homozygous recessive (bb) - blue eyes
Therefore, there is no single answer to your question. The probability depends on the genotype of both parents and which trait is being considered.