When A father is 32 years older than his son in 4 the will be 5 times as old how each now?

Let the son's current age be S years and the father's current age be F years.

We are given that the father is 32 years older than his son:

F = S + 32 (Equation 1)

In 4 years, the son will be S + 4 years old and the father will be F + 4 years old. At that time, the father will be 5 times as old as the son:

F + 4 = 5(S + 4) (Equation 2)

Now we can solve this system of equations. Substitute Equation 1 into Equation 2:

(S + 32) + 4 = 5(S + 4)

S + 36 = 5S + 20

36 - 20 = 5S - S

16 = 4S

S = 4

Now substitute S = 4 back into Equation 1 to find the father's age:

F = 4 + 32

F = 36

Therefore, the son is currently 4 years old, and the father is currently 36 years old.