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If Tanya is eighteen years old her brother Shawn sixteen younger how will be when she three times as Shawn?

Here's how to solve this problem:

1. Find Shawn's current age:

* Shawn is 16 years younger than Tanya, so he is 18 - 16 = 2 years old.

2. Set up an equation:

* Let 'x' be the number of years it takes for Tanya to be three times Shawn's age.

* In 'x' years, Tanya will be 18 + x years old.

* In 'x' years, Shawn will be 2 + x years old.

* We want Tanya's age to be three times Shawn's age, so: 18 + x = 3(2 + x)

3. Solve the equation:

* 18 + x = 6 + 3x

* 12 = 2x

* x = 6

4. Find their ages when Tanya is three times Shawn's age:

* Tanya will be 18 + 6 = 24 years old.

* Shawn will be 2 + 6 = 8 years old.

Answer: Tanya will be 24 years old when she is three times Shawn's age (who will be 8 years old).

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