How to Determine a Resultant Vector

Vectors are like numbers in that they both express magnitude, but unlike numbers, vectors also express direction. A convenient way to represent a vector is with an arrow, where the length of the arrow corresponds to its magnitude. Since the concept of direction is independent of location, a vector's placement is a matter of preference. Place the tail of the arrow at the origin of the Cartesian coordinate system so that its three (x, y, z) coordinates specify the head of the arrow. By this means, vectors make working with three dimensions much easier than with traditional geometry.

Instructions

    • 1

      Find the sum of each of the component vectors to determine the resultant vector. Use the following notation to express vectors: Ai + Bj + Ck, where i, j and k are units vectors pointing in the direction of the positive x, y and z axes respectively. A, B and C are the magnitudes in each of those directions. Adding vectors is simply a matter of finding the sum of each of the coefficients. For example: (2i + 2j + 2k) + (2i + 3j + 4k) = 4i + 5j + 6k.

    • 2

      Calculate the magnitude of the resultant vector using the Pythagorean theorem. This theorem states that the length of a diagonal is the square root of the sum of the squares of the sides. You can picture the coefficients of a vector as the lengths of a box's sides, and the resultant vector is a diagonal extending across opposite corners of the box. Square each of the coefficients, add them up and find the square root. For example, the magnitude of the vector 4i + 5j + 6k is (4^2 + 5^2 + 6^2)^1/2 = 8.77.

    • 3

      Find the direction cosines with respect to each of the axes. The cosine of the angle that the vector forms with respect to a given axis equals the magnitude of the component vector along that axis divided by the overall magnitude. Expressing that for the x-axis: cos(Ax) = Mx/M, where Ax is the angle with respect to the x-axis, Mx is the component magnitude along the x-axis and M is the overall magnitude. For example, the magnitude of the vector 4i + 5j + 6k along the y-axis is 5, so the cosine of the angle that the vector makes with the y-axis is cos(Ay) = 5/8.77 = 0.570. Therefore the angle with respect to the y-axis is arccos(0.570) = 55.2 degrees.

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