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How to Find a Line Parallel to Another Line With 2 Points From the Graph

In geometry, two lines are parallel when they have the same slope -- a concept that describes a line's relation to the x-axis. A line that is parallel to the x-axis has a slope of zero. As the line becomes steeper and steeper going uphill, the slope of the line becomes more and more positive. As the line becomes steeper and steeper going downhill, the slope of the line becomes more and more negative.

Instructions

    • 1

      Choose any two points on a line to determine the slope of the line. If the points are (x1, y1) and (x2, y2), the slope will be (y1 - y2) / (x1 - x2). You can think of this as drawing a little triangle beneath the line. The height of the triangle is y1 - y2 and the base of the triangle is x1 - x2. The hypotenuse is a the line segment between the two points. If the line were turned so that it became steeper, the height of the triangle would become larger with respect to the base -- so the slope increases.

    • 2

      Find a line parallel to a given line and through a given point. If the formula for the given line is y = ax + b, in which "a" is the slope and "b" is the y-intercept, the slope of both lines is the same. If the new line goes through point (x1, y1), you can put x1 and y1 in the formula to get y1 = ax1 + b and solve for b to get the new formula. For example, the line through the point (2, 5) and parallel to the line y = 3x + 1 would be y = 3x + b. To find the b, solve 5 = 3 * 2 + b to get b = -1, so the new line is y = 3x -1.

    • 3

      Draw the line through points (x1, y1) and (x2, y2) by finding the "a" and "b" in y = ax + b. The slope is a = (y1 - y2) / (x1 - x2). Find the "b" by substituting either point in the equation and solving for b. For example, The line through points (0, 3) and (1, 5) has slope (3 - 5) / (0 -1) = -2/-1 = 2. Substituting in y = 2x + b the point (0, 3), you get 3 = 0 + b, so the desired line is y = 2x + 3.

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