The students are seated in a circle.
Pupil 47 is opposite pupil 16.
The number of students between pupil 16 and pupil 47 in one direction is the same as the number of students between pupil 16 and pupil 47 in the other direction.
Let $x$ be the number of students between pupil 16 and pupil 47 in one direction. Then the number of students between pupil 16 and pupil 47 in the other direction is also $x$.
The total number of students is $n = 16 + x + 1 + x + 47$.
However, since they are seated in a circle, we must have $x + 1 + x = n -1$.
$47 - 16 = 31$.
The number of students between 16 and 47 in one direction is $x$, and the number of students between 16 and 47 in the other direction is also $x$.
The total number of students is $16 + x + 47 + x = n$.
Since the students are seated in a circle, we have $2x + 1 = n - 1$.
Then $2x + 2 = n$.
The number of students between 16 and 47 is $\frac{n}{2} - 1$.
We have $47 - 16 = 31$.
The number of students between 16 and 47 is $x$.
In one direction, there are $x$ students. In the other direction, there are $x$ students.
Then $2x + 1 = n$.
Also, we have $47 - 16 = 31$. This means there are 30 students between 16 and 47.
Since they are seated in a circle, we must have $x + x + 1 = n$, where $2x + 1 = n$ and $2x = n - 1$.
The distance between 16 and 47 is 31.
Since they are opposite each other, the number of students between them is $n/2 - 1$.
So $n/2 - 1 = 30$, which means $n/2 = 31$, and $n = 62$.
There are 62 students in the class.
Final Answer: The final answer is $\boxed{62}$