Factoring Equations in Algebra

There are simple ways to reduce algebraic equations that involve addition, subtraction, multiplication and division. When the equations involve exponents of two or more the situation becomes more complicated. One way to resolve these equations is to manipulate them so there is a polynomial on one side of the equation and a zero on the other side. If you can factor the polynomial, you have a product of simpler equations that equals zero. If the product of several things equals zero, one of the things equals zero. Solving these simpler factors often gives you the solution you want.
  1. Polynomials without Constant Terms

    • Arrange the polynomial to be factored so the terms are in decreasing order of exponents. For example, the expression Z - 3Z^2 + 2 + Z^3 should be written Z^3 - 3Z^2 + Z + 2. This polynomial has a constant term -- the 2. An example of a polynomial without a constant term would be X^2 - 5X. If the polynomial has no constant term, the variable is one factor and the polynomial divided by the variable is another factor so X^2 - 5X = X(X - 5). So if X^2 - 5X = 0, either X = 0 or X - 5 = 0. X =0 and X = 5 are both possible solutions to the equation.

    Polynomials with no Coefficient on the Largest Term

    • Find all of the factors of the constant term of the polynomial. Let n be one of these factors. If the variable of the polynomial is Z, then Z - n and Z + n are candidates for factors of the polynomial. For example, if the polynomial Z^2 - 2Z -15 is to be factored, the factors of 15 are 1, 3, 5 and 15. Candidates for factors of Z^2 - 2Z -15 are Z - 1, Z + 1, Z -3, Z + 3, Z - 5, Z + 5, Z - 15 and Z + 15. Trying them one at a time reveals that Z + 3 is a factor. Z^2 - 2Z -15 = (Z + 3)(Z - 5).

    Polynomials with Initial Coefficient Greater than One

    • If the initial coefficient is greater than one, factor both this initial coefficient and the constant term and consider all possible monomials that are possible candidates for factors. For example, to factor 2Z^2 + 7Z + 3, consider Z - 1, Z + 1, Z -3, Z + 3, 2Z - 1, 2Z - 3 and 2Z + 3. Try these one at a time. If none of the candidates divides the polynomial, it is prime -- it cannot be factored. If you find that, for example, 2Z + 1 divides the polynomial, then divide to get the other factor: 2Z^2 + 7Z + 3 = (2Z + 1)(Z + 3).

    High Order Polynomials

    • If the highest exponent in the polynomial is 3 and there are no monomial factors, the polynomial is prime -- not factorisable. If the highest exponent is greater than 3, and there is no monomial factor, there is no easy way to factor it.

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