Help on How to Solve Quadratic Equations for College Algebra

A quadratic equation has a degree of 2, which means the highest exponent of the variable in the equation is 2, such as x^2 + x + 4 = 0. This differs from a linear equation, which has a degree of 1. You can solve quadratic equations using the quadratic formula x = [-b +/- sqrt(b^2 - 4ac)]/2a. With this method you plug numbers from the quadratic equation into the formula and solve for x. The quadratic formula can solve all quadratic equations, whereas other methods may prove difficult for some equations.

Instructions

    • 1

      Choose a quadratic equation that you want to solve. For example, solve the quadratic equation x^2 + 3x = -2.

    • 2

      Rearrange the equation into the standard form, which is ax^2 + bx + c = 0. In the standard form, a and b represent the coefficients in front of the variable and c represents the constant number. In the example, add 2 to both sides of the equation to move -2 to the left side, which results in x^2 + 3x + 2 = -2 + 2. This leaves x^2 + 3x + 2 = 0.

    • 3

      Determine the numbers in the quadratic equation that represent a, b and c. In the example, 1, 3 and 2 represent a, b, and c, respectively.

    • 4

      Plug the numbers for a, b and c into the quadratic formula. In the example, this yields the quadratic formula x = [-3 +/- sqrt(3^2 - 4(1)(2))]/[2(1)]. In the formula, sqrt represents square root.

    • 5

      Square b inside the square root sign. In the example, square 3 to get 9.

    • 6

      Multiply 4 by a by c inside the square root sign. In the example, multiply 4 by 1 by 2, which equals 8.

    • 7

      Subtract the result of 4ac from the result of b^2 inside the square root sign. In the example, subtract 8 from 9, which equals 1. This leaves x = [-3 +/- sqrt(1)]/[2(1)].

    • 8

      Calculate the square root of the number in the square root sign. In the example, calculate the square root of 1, which equals 1. This leaves x = (-3 +/- 1)/[2(1)].

    • 9

      Multiply 2 by a in the denominator. In the example, multiply 2 by 1, which equals 2. This leaves x = (-3 +/- 1)/2.

    • 10

      Separate the formula into two formulas -- one with a "+" sign in the numerator and one with a "-" sign -- to separate the +/- sign in the numerator. This means the equation will have two solutions. In the example, this results in x = (-3 + 1)/2 and x = (-3 - 1)/2.

    • 11

      Add the numbers in the numerator of the first equation. In the example, add -3 to 1, which equals -2. This leaves x = -2/2.

    • 12

      Divide the numerator by the denominator to solve for x. In the example, divide -2 by 2, which equals -1. This leaves x = -1, which means -1 is the first solution.

    • 13

      Subtract the numbers in the numerator of the second equation. In the example, subtract 1 from -3, which equals -4. This leaves x = -4/2.

    • 14

      Divide the numerator by the denominator to solve for x. In the example, divide -4 by 2, which equals -2. This leaves x = -2, which means -2 is the second solution. So the solutions to the quadratic equation are -1 and -2.

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