To find the difference between four-fourths and three-fourths, we subtract the two fractions:
$$\frac{4}{4} - \frac{3}{4} = \frac{4-3}{4} = \frac{1}{4}$$
Thus, four-fourths exceeds three-fourths by $\frac{1}{4}$.
The fractional part by which four-fourths exceeds three-fourths is $\frac{1}{4}$.
Final Answer: The final answer is $\boxed{\frac{1}{4}}$