- Volume of the rock, \(V = 22.7 \texttt{ ml}\)
- Mass of the rock, \(m = 39.943 \texttt{ g}\)
To find:
- Density of the rock, \(\rho\)
Formula:
The density of an object is defined as its mass per unit volume. Mathematically, it can be expressed as:
$$\rho = \frac{m}{V}$$
where:
- \(\rho\) is the density in \(\texttt{g/ml}\)
- \(m\) is the mass in \(\texttt{g}\)
- \(V\) is the volume in \(\texttt{ml}\)
Calculation:
Substituting the given values into the formula, we get:
$$\rho = \frac{39.943 \texttt{ g}}{22.7 \texttt{ ml}} = 1.76 \texttt{ g/ml}$$
Therefore, the density of the rock is \(1.76 \texttt{ g/ml}\).