How to Factor 5th Order Polynomials

In the early part of the 19th century, Evariste Galois proved that there could be no general algebraic solution to fifth-order polynomials. Algebraic solutions to all lower order polynomials had been know for centuries. There are, however, some techniques that often work for some fifth-order equations. Using a tool that Galois could only dream about -- the drafting calculator -- we can see the size of the the fifth-order polynomial factors even if we can not see exactly what the factors are.

Things You'll Need

  • A Graphing Calculator
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Instructions

    • 1

      Graph the fifth-order polynomial on a graphing calculator. The places where the graphed curve crosses the X axis represent real valued roots of the polynomial. If p is such a point, the monomial X - p is a factor of the polynomial. For example, if the graph crosses the X axis at +3, X - 3 is a factor of the polynomial. You should note that if the curve crosses the X axis at 2/3 it is more likely that the monomial factor is 3X - 2 than it is that the factor is X - 2/3. Same root, different monomials.

    • 2

      Find candidates for monomial factors of the polynomial, consider all combinations of the factors of the first and last number in the polynomial. For example, for the fifth-order polynomial 2X^5 - 5X^4 - 6X^3 + 8X^2 + 4X + 3, the first number is 2 which has factors 1 and 2, and the last number is 3 which has factors 1 and 3. Candidate monomial divisors include X - 1, X + 1, X - 3, X + 3, 2X -1, 2X + 1, 2X - 3 and 2X + 3. Trying these one at a time, we find that X -1, X + 1, X - 3 and 2X + 1 all divide the polynomial.

    • 3

      The tricky part of this factoring is that this is only four factors and there should be 5 because it is a fifth order polynomial. Complex roots always come in pairs so the missing factor cannot be complex. A little investigation reveals that (X + 1) is a multiple root so 2X^5 - 5X^4 - 6X^3 + 8X^2 + 4X + 3 = (X - 1)(X + 1)(X + 1)(X - 3)(2X + 1).

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